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What is the output of the program? #include using namespace std; #define SQR(x)(x*x) int main(int argc, char *argv[]) { int x, y=2; x = SQR(y); cout << x << ", " <

}

What happens when you attempt to compile and run the following code? #include using namespace std; int main() { int i, j; for(i = 0; i < 2; i++) { for(j = i; j < i + 1; j++) if(j == i) continue; else break; } cout << j; return 0; }

#include

using namespace std;

void print(char *c);

int main (int argc, const char * argv[])

{

print("Test");

return 0;

}

void print(char *c)

{

cout<

}

Which code line inserted instead of the comment below will fix the program so that it produces the expected output and does not cause any memory leak? 

What happens when you attempt to compile and run the following code? #include using namespace std; int main() { int i, j; for(i = 0; i < 2; i++) { for(j = i; j < i + 1; j++) if(j == i) continue; else break; } cout << j; return 0; }